h^2+8h=560

Solution for h^2+8h=560 equation:

h^2+8h=560

We move all terms to the left:

h^2+8h-(560)=0

a = 1; b = 8; c = -560;
Δ = b2-4ac
Δ = 82-4·1·(-560)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-48}{2*1}=\frac{-56}{2}
=-28
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+48}{2*1}=\frac{40}{2}
=20
$